| Question | Answer |
| force = | mass x acceleration |
| kinetic energy = | 0.5 x mass x \[speed^2\] |
| momentum = | mass x velocity |
| work done = | force x distance (along the line of action of the force) |
| power = | work done ÷ time |
| efficiency = | output energy transfer ÷input energy transfer |
| gravity force = | mass x gravity constant (g) |
| in a gravity field: potential energy = | mass x height x gravity constant (g) |
| force exerted by a spring = | extension x spring constant |
| moment of a force = | force x distance (normal to direction of the force) |
| distance travelled = | speed x time |
| acceleration = | change in velocity ÷ time |
| wave speed = | frequency x wavelength |
| charge flow = | current x time |
| potential difference = | current x resistance |
| power = potential difference x current = | \[current^2\] x resistance |
| energy transferred = | power x time = charge flow x potential difference |
| density = | mass ÷volume |
| pressure = | force normal to a surface ÷ area of that surface |
| \[final velocity^2\] - \[initial velocity^2\] = | 2 x acceleration x distance |
| change in thermal energy = | m x specific heat capacity x change in temperature |
| thermal energy for a change of state = | m x specific latent heat |
| energy transferred in stretching = | 0.5 x spring constant x \[extension^2\] |
| potential difference across primary coil x current in primary coil = | potential difference across secondary coil x current in secondary coil |
| for gases: pressure x volume = | constant (for a given mass of gas and at a constant temperature) |
| Higher tier only: force on a conductor (at right angles to a magnetic field) carrying a current = | magnetic flux density x current x length |
| Higher tier only: potential difference across primary coil ÷potential difference across secondary coil = | number of turns in primary coil ÷number of turns in secondary coil |
| Higher tier only: pressure due to a column of liquid = | height of column x density of liquid x g |
Want to create your own Flashcards for free with GoConqr? Learn more.